http://www.youtube.com/watch?v=97du1N7Znb0
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it's purely math but it's a special one alrigth. :shrug: can't say anything besides that
http://www.youtube.com/watch?v=gENVB6tjq_M&list=PL1B8F54EE80413737
oh ho, this muddies the issue
Assuming the ride empties out as it approaches the 30 minute mark, it'd go
10=2
10:01=4
10:02=6
etc until it reaches 20 people on the ride, with 2 coming off and 2 getting on each minute, until 10:21, when 2 people get off and no one gets on
This way would make the total 42
@Wandergirl108 MATHS! :egghead:
That's right!
For the first nine minutes the Ferris wheel is moving, the cars arriving at the unloading zone are unoccupied. For the last nine minutes of operation, needless to say, no one will be allowed to board the cars.
From the time the Ferris wheel fills up at 10 minutes past the hour until the last passenger steps off at 10:30, a total of 21 sets of passengers will have taken a ride on the Ferris wheel.
Just clarifying it how i see it
last one for today
riddle 63:
You've placed one joker and four aces with different suits facedown on a table. Use the hints below to determine the position for each card.
1. The club is to the immediate right of the heart.
2. Neither the diamond nor the joker is next to the spade.
3. Neither the joker nor the diamond is next to the club.
4. Neither the diamond nor the spade is next to the heart.
Hello again, Slowking
Using the simple logic of
D+H=Not Sp
J+D= Not Cl
D+Sp=Not H
Club TTR of H
Then The Club and Heart will always be together, regardless, making those two go H,C.
Neither the Diamond or the Spade are next to the Heart, and the Diamond is also not next to Club, meaning it must go to the left or right of them, with something in between. The Joker does not go next to the club OR the spade, meaning that it must go between the Diamond and the Heart. etc etc etc
Basically the line goes:
Diamond Joker Heart Club Spade
riddle 64:
let's say x are filled glasses and I are empty glasses.
you have XXXIII
turn it into XIXIXI
change things around so that the cups are arranged as shown in the bottom row.
Assuming you can only move one cup at a time and that all rearrangement has to be done by hand, how many cups will you have to pick up? and how did you do it?
Technically you wouldn't have to pick any up as you could just move them in order.
But let's say we only could pick them up I would say 2.
All you have to do is swap the second x with the one before the last one (caps for the ones that have to change):
xXxiIi
If you swap those two you get the required form.
1. You pick up the second x and pour the water in the one before the last.
put a little extra work into this one, made a picture to make it more clear out of different vectors I stored a long time ago. I'd suggest working on the picture provided in paint if remembering from the mind is a tad hard
riddle 65:
Below there are 16 cards, 4 have already been placed. There are 4 of each suit (diamonds, clubs, hearts,spades). As shown below you get a 4x4 grid with 4 cards placed already.
Arrange the cards so that each vertical collumn, horizontal row and diagonal line of 4 cards has one card of each suit.
http://i47.tinypic.com/f309s.png
you can either type out the answer or use paint or perhaps draw it and then work further from there. doing this from the mind is very hard. idc really as long as it's correct and understandable.
http://i.imgur.com/hFG440Rs.png
Spoiler: Large
:c back to my riddlehate for me to come up with a harder one. Thought it would be hard enough since not everyone knows how to use paint so well. oh well :venture:
i'll edit this one with the 67th one :shrug: (i'll kill the first one that makes a 69 joke when we get that far >.>)
riddle 67:
http://www.youtube.com/watch?v=gENVB6tjq_M
yup sorry but since brae wanted to know an example of one i refuse to post as I consider them too hard :shrug: i'll post the simplified version of the easiest one of the list.
Ok so I'm posting a number cycle, fill in the "?"
4 -> 16 -> 37 -> 58 -> ? -> 145 -> 42 -> 20 -> ... start from the front again
So yea enjoy finding the pattern, if you people find it too ahrd go nag @Braeburn
:hai: Oh this came close to sending me on completely the wrong path... but then I had a moment of pure brilliance and got the answer!
Short answer = 89
Long Answer:
The process of each step is to take each individual digit of each point, square them, and then add the two answers together, as shown below:
Step 1: 4
Step 2: 4^2 = 16
Step 3: 1^2 + 6^2 = 37
Step 4: 3^2 + 7^2 = 58
Step 5: 5^2 + 8^2 = 89
Step 6: 8^2 + 9^2 = 145
Step 7: 1^2 + 4^2 + 5^2 = 42
Step 8: 4^2 + 2^2 = 20
Step 9: 2^2 + 0^2 = 4
AND REPEAT :D
ok last one for today @Braeburn
riddle 68:
4 students took a test where questions had 2 posisble answers, A and B. Each questions was worth 10 points for a total of 100 points.
The students score were posted as seen below. but the teacher forgot collin's score. The students calculated his score using their own results. Can you figure out Collin's score?
Marry
1 2 3 4 5 6 7 8 9 10
B B A B A B B A B B = 70
Dan
1 2 3 4 5 6 7 8 9 10
B A A A B A BA A A = 50
Lisa
1 2 3 4 5 6 7 8 9 10
B A A A B B B A B A = 30
Collin
1 2 3 4 5 6 7 8 9 10
B B A A A B B A A A = ???????
what is collins score and how did you get it?
Oh boy, more math! @Wandergirl108, race ya!
@Slowking @Wandergirl108
http://i.imgur.com/BGrtm0n.png
:venture:
The answer is 60 BTW
that's an A+ for you... sadly collin only got 60 (badum tsss) :lol:
indeed all you have to do is make an answer key and there are 4 possible ones from the things i gave you
possible answer keys:
BBBBAABAAB
BBABAABBAB
BBABAAAAAB
ABABAABAAB
doesn't matter what one you end up with it'll always give you 60 :shrug:
riddle 69:
AB:CD x3
= EF : G7
fill in the numbers 1,2,4,5,6,8 and 9 to form a correct equation